If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X=36-X^2
We move all terms to the left:
X-(36-X^2)=0
We get rid of parentheses
X^2+X-36=0
a = 1; b = 1; c = -36;
Δ = b2-4ac
Δ = 12-4·1·(-36)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{145}}{2*1}=\frac{-1-\sqrt{145}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{145}}{2*1}=\frac{-1+\sqrt{145}}{2} $
| 5=10÷c | | 4x+5+x+15=180 | | 2y-11+y+3=180 | | -f+2+-4f=8-3f | | 1/2x+2/3x+5/3x=3/5 | | -17+b/8=14 | | 17x+7=25x+5 | | x+3/8=7/10 | | -4x+3-3(x+1)=-(5x-1) | | 5x/6-3=2/3+4x/9 | | 3x+4x-3=180 | | 2u/5+u/4=9/5+3/20 | | x+20=-4x-14 | | 5/13=t-6/13t= | | (x-10)(x/2+20)=0 | | (3x+3)2+(4x)2=174 | | -f+2+-4f=8-3f=f | | -2m+m^2-5=0 | | 12x-40=-4 | | 10x-1=25-3x | | 80.8992+8y=121.5 | | 3(14-6)+8(6-x)÷(16÷2)=8 | | -18x/(x^2-9)^2=0 | | 14x+76=76 | | 3x+6+3x-8+110=180 | | 161+8y=121.5 | | 8(b+3)(b-9)=0 | | 8(b+3(b-9)=0 | | 77/30=k+5/3-3/2 | | 3x+6+3x+8=180 | | 4u/5=-12 | | 36-10x=-14 |